What are the solutions to the equation -1/5 x^2+2x-4=0 ?

The solutions to the equation -1/5 x^2+2x-4=0 are x=5-sqrt(5),x=5+sqrt(5)

Find the zeros of -1/5 x^2+2x-4=0

The zeros of -1/5 x^2+2x-4=0 are x=5-sqrt(5),x=5+sqrt(5)

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- \frac{1}{5} x^{2} + 2 x - 4 = 0

x = 5 - 5, x = 5 + 5

Decimal Notation

x = 2.76393 \dots, x = 7.23606 \dots

Solution steps

- \frac{1}{5} x^{2} + 2 x - 4 = 0

Multiply both sides by

5

- x^{2} + 10 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 20) = 25

x_{1, 2} = \frac{- 10 \pm 2 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 5}{2 ( - 1 )}, x_{2} = \frac{- 10 - 2 5}{2 ( - 1 )}

x = \frac{- 10 + 2 5}{2 ( - 1 )} : 5 - 5

x = \frac{- 10 - 2 5}{2 ( - 1 )} : 5 + 5

The solutions to the quadratic equation are:

x = 5 - 5, x = 5 + 5

- x^{2} - 5 x + 6

\frac{1}{2} x^{2} - 5 = - x^{2} + 4.5

2 c^{2} + 15 = - 11 c

21 x^{2} + x - 10 = 0

5 x^{2} + 23 x = 13 x - 10

What are the solutions to the equation -1/5 x^2+2x-4=0 ?
The solutions to the equation -1/5 x^2+2x-4=0 are x=5-sqrt(5),x=5+sqrt(5)
Find the zeros of -1/5 x^2+2x-4=0
The zeros of -1/5 x^2+2x-4=0 are x=5-sqrt(5),x=5+sqrt(5)