What are the solutions to the equation 2c^2+15=-11c ?

The solutions to the equation 2c^2+15=-11c are c=-5/2 ,c=-3

Find the zeros of 2c^2+15=-11c

The zeros of 2c^2+15=-11c are c=-5/2 ,c=-3

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2 c^{2} + 15 = - 11 c

c = - \frac{5}{2}, c = - 3

Decimal Notation

c = - 2.5, c = - 3

Solution steps

2 c^{2} + 15 = - 11 c

Move

11 c

to the left side

2 c^{2} + 15 + 11 c = 0

Write in the standard form

a x^{2} + b x + c = 0

2 c^{2} + 11 c + 15 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 15 = 1

c_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 2}

Separate the solutions

c_{1} = \frac{- 11 + 1}{2 \cdot 2}, c_{2} = \frac{- 11 - 1}{2 \cdot 2}

c = \frac{- 11 + 1}{2 \cdot 2} : - \frac{5}{2}

c = \frac{- 11 - 1}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

c = - \frac{5}{2}, c = - 3

21 x^{2} + x - 10 = 0

5 x^{2} + 23 x = 13 x - 10

9 x^{2} + 8 x - 5 = 0

(x - 4)^{2} - 144 = 0

- X^{2} + 5 X - 100 = 0

What are the solutions to the equation 2c^2+15=-11c ?
The solutions to the equation 2c^2+15=-11c are c=-5/2 ,c=-3
Find the zeros of 2c^2+15=-11c
The zeros of 2c^2+15=-11c are c=-5/2 ,c=-3