What are the solutions to the equation t^2+11/3 t+1=0 ?

The solutions to the equation t^2+11/3 t+1=0 are t=(-11+sqrt(85))/6 ,t=(-11-sqrt(85))/6

Find the zeros of t^2+11/3 t+1=0

The zeros of t^2+11/3 t+1=0 are t=(-11+sqrt(85))/6 ,t=(-11-sqrt(85))/6

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t^{2} + \frac{11}{3} t + 1 = 0

t = \frac{- 11 + 85}{6}, t = \frac{- 11 - 85}{6}

Decimal Notation

t = - 0.29674 \dots, t = - 3.36992 \dots

Solution steps

t^{2} + \frac{11}{3} t + 1 = 0

Multiply both sides by

3

3 t^{2} + 11 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 3 = 85

t_{1, 2} = \frac{- 11 \pm 85}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 11 + 85}{2 \cdot 3}, t_{2} = \frac{- 11 - 85}{2 \cdot 3}

t = \frac{- 11 + 85}{2 \cdot 3} : \frac{- 11 + 85}{6}

t = \frac{- 11 - 85}{2 \cdot 3} : \frac{- 11 - 85}{6}

The solutions to the quadratic equation are:

t = \frac{- 11 + 85}{6}, t = \frac{- 11 - 85}{6}

3 x^{2} - x = x^{2} - 4 x

27 x^{2} = 27

3 (x - 6) = 5 x^{2} + 1

x^{2} - 7 x = - 12

3 x^{2} + 5 x - 28 = 0

What are the solutions to the equation t^2+11/3 t+1=0 ?
The solutions to the equation t^2+11/3 t+1=0 are t=(-11+sqrt(85))/6 ,t=(-11-sqrt(85))/6
Find the zeros of t^2+11/3 t+1=0
The zeros of t^2+11/3 t+1=0 are t=(-11+sqrt(85))/6 ,t=(-11-sqrt(85))/6