What are the solutions to the equation completesquare 3x^2+5x-28=0 ?

The solutions to the equation completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4

Find the zeros of completesquare 3x^2+5x-28=0

The zeros of completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4

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3 x^{2} + 5 x - 28 = 0

x = \frac{7}{3}, x = - 4

Decimal Notation

x = 2.33333 \dots, x = - 4

Solution steps

3 x^{2} + 5 x - 28 = 0

Move

28

to the right side

3 x^{2} + 5 x = 28

Divide both sides by

3

\frac{3 x ^{2} + 5 x}{3} = \frac{28}{3}

x^{2} + \frac{5 x}{3} = \frac{28}{3}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{6})^{2} = \frac{361}{36}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{6} = \frac{361}{36} : x = \frac{7}{3}

Solve

x + \frac{5}{6} = - \frac{361}{36} : x = - 4

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 4

- 15 x^{2} - 3.139 x + 11.25 = 0

k^{2} x^{2} + 6 x = (k + 6) x^{2} - k

81 x^{2} - 289 = 0

0 = - x^{2} + 3 x + 28

x^{2} - x = \frac{1}{3}

What are the solutions to the equation completesquare 3x^2+5x-28=0 ?
The solutions to the equation completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4
Find the zeros of completesquare 3x^2+5x-28=0
The zeros of completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4