What are the solutions to the equation y^2+10y-200=0 ?

The solutions to the equation y^2+10y-200=0 are y=10,y=-20

Find the zeros of y^2+10y-200=0

The zeros of y^2+10y-200=0 are y=10,y=-20

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y^{2} + 10 y - 200 = 0

y = 10, y = - 20

Solution steps

y^{2} + 10 y - 200 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 200 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 200) = 30

y_{1, 2} = \frac{- 10 \pm 30}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 30}{2 \cdot 1}, y_{2} = \frac{- 10 - 30}{2 \cdot 1}

y = \frac{- 10 + 30}{2 \cdot 1} : 10

y = \frac{- 10 - 30}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

y = 10, y = - 20

5 x^{2} + 17 x = 12

5 x^{2} - 20 x = 300

12 x^{2} - 6 x + 2 = 0

2 + 10 x - 4.9 x^{2} = 0

4 x^{2} - 4 x - 3 = 0

What are the solutions to the equation y^2+10y-200=0 ?
The solutions to the equation y^2+10y-200=0 are y=10,y=-20
Find the zeros of y^2+10y-200=0
The zeros of y^2+10y-200=0 are y=10,y=-20