What are the solutions to the equation 2+10x-4.9x^2=0 ?

The solutions to the equation 2+10x-4.9x^2=0 are x=-(2(sqrt(870)-25))/(49),x=(2(25+sqrt(870)))/(49)

Find the zeros of 2+10x-4.9x^2=0

The zeros of 2+10x-4.9x^2=0 are x=-(2(sqrt(870)-25))/(49),x=(2(25+sqrt(870)))/(49)

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2 + 10 x - 4.9 x^{2} = 0

x = - \frac{2 ( 870 - 25 )}{49}, x = \frac{2 ( 25 + 870 )}{49}

Decimal Notation

x = - 0.18350 \dots, x = 2.22431 \dots

Solution steps

2 + 10 x - 4.9 x^{2} = 0

Multiply both sides by

10

20 + 100 x - 49 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 x^{2} + 100 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 49 ) \cdot 20}{2 ( - 49 )}

10 0^{2} - 4 (- 49) \cdot 20 = 4870

x_{1, 2} = \frac{- 100 \pm 4 870}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 100 + 4 870}{2 ( - 49 )}, x_{2} = \frac{- 100 - 4 870}{2 ( - 49 )}

x = \frac{- 100 + 4 870}{2 ( - 49 )} : - \frac{2 ( 870 - 25 )}{49}

x = \frac{- 100 - 4 870}{2 ( - 49 )} : \frac{2 ( 25 + 870 )}{49}

The solutions to the quadratic equation are:

x = - \frac{2 ( 870 - 25 )}{49}, x = \frac{2 ( 25 + 870 )}{49}

4 x^{2} - 4 x - 3 = 0

1 x^{2} - 4 x + 2 = 0

- 3 x^{2} + 5 x = - 2

3 x^{(2)} + 2 x = 11

x^{2} - 5 x = 36

What are the solutions to the equation 2+10x-4.9x^2=0 ?
The solutions to the equation 2+10x-4.9x^2=0 are x=-(2(sqrt(870)-25))/(49),x=(2(25+sqrt(870)))/(49)
Find the zeros of 2+10x-4.9x^2=0
The zeros of 2+10x-4.9x^2=0 are x=-(2(sqrt(870)-25))/(49),x=(2(25+sqrt(870)))/(49)