What are the solutions to the equation 3x^{(2)}+2x=11 ?

The solutions to the equation 3x^{(2)}+2x=11 are x=(-1+sqrt(34))/3 ,x=-(1+sqrt(34))/3

Find the zeros of 3x^{(2)}+2x=11

The zeros of 3x^{(2)}+2x=11 are x=(-1+sqrt(34))/3 ,x=-(1+sqrt(34))/3

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3 x^{(2)} + 2 x = 11

x = \frac{- 1 + 34}{3}, x = - \frac{1 + 34}{3}

Decimal Notation

x = 1.61031 \dots, x = - 2.27698 \dots

Solution steps

3 x^{(2)} + 2 x = 11

Refine

3 x^{2} + 2 x = 11

Move

11

to the left side

3 x^{2} + 2 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 11 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 11) = 234

x_{1, 2} = \frac{- 2 \pm 2 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 34}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 34}{2 \cdot 3}

x = \frac{- 2 + 2 34}{2 \cdot 3} : \frac{- 1 + 34}{3}

x = \frac{- 2 - 2 34}{2 \cdot 3} : - \frac{1 + 34}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 34}{3}, x = - \frac{1 + 34}{3}

x^{2} - 5 x = 36

x, x (x - y) = \frac{1}{2}

(2 x + 1) (x) = 66

- x^{2} + \frac{5}{6} x + 1 = 0

\frac{1}{3} (2 x + 3)^{2} = 2

What are the solutions to the equation 3x^{(2)}+2x=11 ?
The solutions to the equation 3x^{(2)}+2x=11 are x=(-1+sqrt(34))/3 ,x=-(1+sqrt(34))/3
Find the zeros of 3x^{(2)}+2x=11
The zeros of 3x^{(2)}+2x=11 are x=(-1+sqrt(34))/3 ,x=-(1+sqrt(34))/3