What are the solutions to the equation 3(3x-2)^2=-2(3x-2) ?

The solutions to the equation 3(3x-2)^2=-2(3x-2) are x= 2/3 ,x= 4/9

Find the zeros of 3(3x-2)^2=-2(3x-2)

The zeros of 3(3x-2)^2=-2(3x-2) are x= 2/3 ,x= 4/9

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3 (3 x - 2)^{2} = - 2 (3 x - 2)

x = \frac{2}{3}, x = \frac{4}{9}

Decimal Notation

x = 0.66666 \dots, x = 0.44444 \dots

Solution steps

3 (3 x - 2)^{2} = - 2 (3 x - 2)

Move

2 (3 x - 2)

to the left side

3 (3 x - 2)^{2} + 2 (3 x - 2) = 0

Factor

3 (3 x - 2)^{2} + 2 (3 x - 2) : (3 x - 2) (9 x - 4)

(3 x - 2) (9 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 9 x - 4 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

9 x - 4 = 0 : x = \frac{4}{9}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = \frac{4}{9}

- 2 x^{2} + 240 x - 5500 = 0

(x + 13)^{2} = 21

x, (x - 1)^{2} = 9

x, f (x - 3) = 4 x^{2} - 5 x

b, a (a + b) (a + b + c) = 11

What are the solutions to the equation 3(3x-2)^2=-2(3x-2) ?
The solutions to the equation 3(3x-2)^2=-2(3x-2) are x= 2/3 ,x= 4/9
Find the zeros of 3(3x-2)^2=-2(3x-2)
The zeros of 3(3x-2)^2=-2(3x-2) are x= 2/3 ,x= 4/9