What are the solutions to the equation (x)=3x^2-48x+350 ?

The solutions to the equation (x)=3x^2-48x+350 are x= 49/6+i(sqrt(1799))/6 ,x= 49/6-i(sqrt(1799))/6

Find the zeros of (x)=3x^2-48x+350

The zeros of (x)=3x^2-48x+350 are x= 49/6+i(sqrt(1799))/6 ,x= 49/6-i(sqrt(1799))/6

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(x) = 3 x^{2} - 48 x + 350

x = \frac{49}{6} + i \frac{1799}{6}, x = \frac{49}{6} - i \frac{1799}{6}

Solution steps

(x) = 3 x^{2} - 48 x + 350

Refine

x = 3 x^{2} - 48 x + 350

Switch sides

3 x^{2} - 48 x + 350 = x

Move

x

to the left side

3 x^{2} - 49 x + 350 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 3 \cdot 350}{2 \cdot 3}

Simplify

(- 49)^{2} - 4 \cdot 3 \cdot 350 : 1799 i

x_{1, 2} = \frac{- ( - 49 ) \pm 1799 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 49 ) + 1799 i}{2 \cdot 3}, x_{2} = \frac{- ( - 49 ) - 1799 i}{2 \cdot 3}

x = \frac{- ( - 49 ) + 1799 i}{2 \cdot 3} : \frac{49}{6} + i \frac{1799}{6}

x = \frac{- ( - 49 ) - 1799 i}{2 \cdot 3} : \frac{49}{6} - i \frac{1799}{6}

The solutions to the quadratic equation are:

x = \frac{49}{6} + i \frac{1799}{6}, x = \frac{49}{6} - i \frac{1799}{6}

(x - 6)^{2} + 10 (x - 6) = 0

(x + 13)^{2} = - 9

6 x^{2} - 80 x + 160 = 0

y^{2} = 2 y - 8

x^{2} - 4 x + 3 = x + 3

What are the solutions to the equation (x)=3x^2-48x+350 ?
The solutions to the equation (x)=3x^2-48x+350 are x= 49/6+i(sqrt(1799))/6 ,x= 49/6-i(sqrt(1799))/6
Find the zeros of (x)=3x^2-48x+350
The zeros of (x)=3x^2-48x+350 are x= 49/6+i(sqrt(1799))/6 ,x= 49/6-i(sqrt(1799))/6