What are the solutions to the equation 6x^2-80x+160=0 ?

The solutions to the equation 6x^2-80x+160=0 are x=(4(5+sqrt(10)))/3 ,x=(4(5-sqrt(10)))/3

Find the zeros of 6x^2-80x+160=0

The zeros of 6x^2-80x+160=0 are x=(4(5+sqrt(10)))/3 ,x=(4(5-sqrt(10)))/3

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6 x^{2} - 80 x + 160 = 0

x = \frac{4 ( 5 + 10 )}{3}, x = \frac{4 ( 5 - 10 )}{3}

Decimal Notation

x = 10.88303 \dots, x = 2.45029 \dots

Solution steps

6 x^{2} - 80 x + 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 6 \cdot 160}{2 \cdot 6}

(- 80)^{2} - 4 \cdot 6 \cdot 160 = 1610

x_{1, 2} = \frac{- ( - 80 ) \pm 16 10}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 16 10}{2 \cdot 6}, x_{2} = \frac{- ( - 80 ) - 16 10}{2 \cdot 6}

x = \frac{- ( - 80 ) + 16 10}{2 \cdot 6} : \frac{4 ( 5 + 10 )}{3}

x = \frac{- ( - 80 ) - 16 10}{2 \cdot 6} : \frac{4 ( 5 - 10 )}{3}

The solutions to the quadratic equation are:

x = \frac{4 ( 5 + 10 )}{3}, x = \frac{4 ( 5 - 10 )}{3}

y^{2} = 2 y - 8

x^{2} - 4 x + 3 = x + 3

3 (x + 4)^{2} - 81 = 0

5 r^{2} - 10 r = 0

24 x^{2} - 12 x = 36 x

What are the solutions to the equation 6x^2-80x+160=0 ?
The solutions to the equation 6x^2-80x+160=0 are x=(4(5+sqrt(10)))/3 ,x=(4(5-sqrt(10)))/3
Find the zeros of 6x^2-80x+160=0
The zeros of 6x^2-80x+160=0 are x=(4(5+sqrt(10)))/3 ,x=(4(5-sqrt(10)))/3