What are the solutions to the equation 0=-1000(x^2)+300x+1000 ?

The solutions to the equation 0=-1000(x^2)+300x+1000 are x=-(-3+sqrt(409))/(20),x=(3+sqrt(409))/(20)

Find the zeros of 0=-1000(x^2)+300x+1000

The zeros of 0=-1000(x^2)+300x+1000 are x=-(-3+sqrt(409))/(20),x=(3+sqrt(409))/(20)

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0 = - 1000 (x^{2}) + 300 x + 1000

x = - \frac{- 3 + 409}{20}, x = \frac{3 + 409}{20}

Decimal Notation

x = - 0.86118 \dots, x = 1.16118 \dots

Solution steps

0 = - 1000 (x^{2}) + 300 x + 1000

Refine

0 = - 1000 x^{2} + 300 x + 1000

Switch sides

- 1000 x^{2} + 300 x + 1000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 1000 ) \cdot 1000}{2 ( - 1000 )}

30 0^{2} - 4 (- 1000) \cdot 1000 = 100409

x_{1, 2} = \frac{- 300 \pm 100 409}{2 ( - 1000 )}

Separate the solutions

x_{1} = \frac{- 300 + 100 409}{2 ( - 1000 )}, x_{2} = \frac{- 300 - 100 409}{2 ( - 1000 )}

x = \frac{- 300 + 100 409}{2 ( - 1000 )} : - \frac{- 3 + 409}{20}

x = \frac{- 300 - 100 409}{2 ( - 1000 )} : \frac{3 + 409}{20}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 409}{20}, x = \frac{3 + 409}{20}

5 n^{2} + 30 n = 0

X^{2} - 14 X + 49 = 0

(x) = 2 x^{2} - 40 x + 1000

(y - 1) (y - 1) = 0

(x - 6) (x + 4) = 3 (x - 5)

What are the solutions to the equation 0=-1000(x^2)+300x+1000 ?
The solutions to the equation 0=-1000(x^2)+300x+1000 are x=-(-3+sqrt(409))/(20),x=(3+sqrt(409))/(20)
Find the zeros of 0=-1000(x^2)+300x+1000
The zeros of 0=-1000(x^2)+300x+1000 are x=-(-3+sqrt(409))/(20),x=(3+sqrt(409))/(20)