What are the solutions to the equation (x)=2x^2-40x+1000 ?

The solutions to the equation (x)=2x^2-40x+1000 are x= 41/4+i(sqrt(6319))/4 ,x= 41/4-i(sqrt(6319))/4

Find the zeros of (x)=2x^2-40x+1000

The zeros of (x)=2x^2-40x+1000 are x= 41/4+i(sqrt(6319))/4 ,x= 41/4-i(sqrt(6319))/4

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(x) = 2 x^{2} - 40 x + 1000

x = \frac{41}{4} + i \frac{6319}{4}, x = \frac{41}{4} - i \frac{6319}{4}

Solution steps

(x) = 2 x^{2} - 40 x + 1000

Refine

x = 2 x^{2} - 40 x + 1000

Switch sides

2 x^{2} - 40 x + 1000 = x

Move

x

to the left side

2 x^{2} - 41 x + 1000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 2 \cdot 1000}{2 \cdot 2}

Simplify

(- 41)^{2} - 4 \cdot 2 \cdot 1000 : 6319 i

x_{1, 2} = \frac{- ( - 41 ) \pm 6319 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 6319 i}{2 \cdot 2}, x_{2} = \frac{- ( - 41 ) - 6319 i}{2 \cdot 2}

x = \frac{- ( - 41 ) + 6319 i}{2 \cdot 2} : \frac{41}{4} + i \frac{6319}{4}

x = \frac{- ( - 41 ) - 6319 i}{2 \cdot 2} : \frac{41}{4} - i \frac{6319}{4}

The solutions to the quadratic equation are:

x = \frac{41}{4} + i \frac{6319}{4}, x = \frac{41}{4} - i \frac{6319}{4}

(y - 1) (y - 1) = 0

(x - 6) (x + 4) = 3 (x - 5)

- 5 x^{2} - 6 = 0

x, x^{2} - 14 x + 35 = - 10

2 \cdot (x + 4)^{2} = x^{2} - 13

What are the solutions to the equation (x)=2x^2-40x+1000 ?
The solutions to the equation (x)=2x^2-40x+1000 are x= 41/4+i(sqrt(6319))/4 ,x= 41/4-i(sqrt(6319))/4
Find the zeros of (x)=2x^2-40x+1000
The zeros of (x)=2x^2-40x+1000 are x= 41/4+i(sqrt(6319))/4 ,x= 41/4-i(sqrt(6319))/4