What are the solutions to the equation 2x^2+50=-166 ?

The solutions to the equation 2x^2+50=-166 are x=6sqrt(3)i,x=-6sqrt(3)i

Find the zeros of 2x^2+50=-166

The zeros of 2x^2+50=-166 are x=6sqrt(3)i,x=-6sqrt(3)i

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2 x^{2} + 50 = - 166

x = 63 i, x = - 63 i

Solution steps

2 x^{2} + 50 = - 166

Move

50

to the right side

2 x^{2} = - 216

Divide both sides by

2

x^{2} = - 108

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 108, x = - - 108

- 108 = 63 i

- - 108 = - 63 i

x = 63 i, x = - 63 i

- 2 (6 w^{2} + 7 w - 210) = 0

\frac{( x - 15 )}{15} + \frac{x}{5} - 1 = 0

12 x^{2} + 7 x - 10

\frac{( x - 1 )}{x - 13} < 0

4 x^{2} + 3 x + 8 = 0

What are the solutions to the equation 2x^2+50=-166 ?
The solutions to the equation 2x^2+50=-166 are x=6sqrt(3)i,x=-6sqrt(3)i
Find the zeros of 2x^2+50=-166
The zeros of 2x^2+50=-166 are x=6sqrt(3)i,x=-6sqrt(3)i