What is the answer to (2x}{4pi}+\frac{1-x)/2 =0 ?

The answer to (2x}{4pi}+\frac{1-x)/2 =0 is x= pi/(pi-1)

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(2x}{4pi}+\frac{1-x)/2 =0

\frac{2 x}{4 π} + \frac{1 - x}{2} = 0

x = \frac{π}{π - 1}

Solution steps

\frac{2 x}{4 π} + \frac{1 - x}{2} = 0

Cancel

\frac{2 x}{4 π} : \frac{x}{2 π}

\frac{x}{2 π} + \frac{1 - x}{2} = 0

Multiply by LCM

x + π (1 - x) = 0

Expand

π (1 - x) : π - π x

x + π - π x = 0

Move

π

to the right side

x - π x = - π

Factor

x - π x : (1 - π) x

(1 - π) x = - π

Divide both sides by

1 - π

x = \frac{π}{π - 1}

x, y = f (x - 3) + 2

9 = - \frac{7}{10} a - 12

\frac{5 r}{2} - 6 = 19

r, r - rs = 2 rs + 5

3 x - 8 (2 x + 3) = - 6 (2 x + 5)

What is the answer to (2x}{4pi}+\frac{1-x)/2 =0 ?
The answer to (2x}{4pi}+\frac{1-x)/2 =0 is x= pi/(pi-1)