What are the solutions to the equation 17k^2-221k=0 ?

The solutions to the equation 17k^2-221k=0 are k=13,k=0

Find the zeros of 17k^2-221k=0

The zeros of 17k^2-221k=0 are k=13,k=0

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17 k^{2} - 221 k = 0

k = 13, k = 0

Solution steps

17 k^{2} - 221 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 221 ) \pm ( - 221 ) ^{2} - 4 \cdot 17 \cdot 0}{2 \cdot 17}

(- 221)^{2} - 4 \cdot 17 \cdot 0 = 221

k_{1, 2} = \frac{- ( - 221 ) \pm 221}{2 \cdot 17}

Separate the solutions

k_{1} = \frac{- ( - 221 ) + 221}{2 \cdot 17}, k_{2} = \frac{- ( - 221 ) - 221}{2 \cdot 17}

k = \frac{- ( - 221 ) + 221}{2 \cdot 17} : 13

k = \frac{- ( - 221 ) - 221}{2 \cdot 17} : 0

The solutions to the quadratic equation are:

k = 13, k = 0

3 z^{2} - 8 z + 2 = 0

n^{4} + 8 n^{2} + 15

(x - 1)^{\frac{1}{3}} - (x^{2} - x) (x - 1)^{- \frac{2}{3}}

e^{3 l n (3)}

(2 t)^{\frac{3}{2}}

What are the solutions to the equation 17k^2-221k=0 ?
The solutions to the equation 17k^2-221k=0 are k=13,k=0
Find the zeros of 17k^2-221k=0
The zeros of 17k^2-221k=0 are k=13,k=0