What are the solutions to the equation x^2-14x=15 ?

The solutions to the equation x^2-14x=15 are x=15,x=-1

Find the zeros of x^2-14x=15

The zeros of x^2-14x=15 are x=15,x=-1

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x^{2} - 14 x = 15

x = 15, x = - 1

Solution steps

x^{2} - 14 x = 15

Move

15

to the left side

x^{2} - 14 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 15) = 16

x_{1, 2} = \frac{- ( - 14 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 16}{2 \cdot 1}

x = \frac{- ( - 14 ) + 16}{2 \cdot 1} : 15

x = \frac{- ( - 14 ) - 16}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 15, x = - 1

10 s^{2} - 24 s - 152 = 0

5 x - 18 \geq - 8

\frac{5}{2 5}

- \frac{1}{8} (x + 3)^{2} = 7

8 x + 38 = - 3 (- 6 - 4 x)

What are the solutions to the equation x^2-14x=15 ?
The solutions to the equation x^2-14x=15 are x=15,x=-1
Find the zeros of x^2-14x=15
The zeros of x^2-14x=15 are x=15,x=-1