What are the solutions to the equation -3x^2-4x+4=0 ?

The solutions to the equation -3x^2-4x+4=0 are x=-2,x= 2/3

Find the zeros of -3x^2-4x+4=0

The zeros of -3x^2-4x+4=0 are x=-2,x= 2/3

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- 3 x^{2} - 4 x + 4 = 0

x = - 2, x = \frac{2}{3}

Solution steps

- 3 x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 3 ) \cdot 4}{2 ( - 3 )}

(- 4)^{2} - 4 (- 3) \cdot 4 = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 ( - 3 )}, x_{2} = \frac{- ( - 4 ) - 8}{2 ( - 3 )}

x = \frac{- ( - 4 ) + 8}{2 ( - 3 )} : - 2

x = \frac{- ( - 4 ) - 8}{2 ( - 3 )} : \frac{2}{3}

The solutions to the quadratic equation are:

x = - 2, x = \frac{2}{3}

- 4 e - 9 = 19

[3 k + 19] < 5

m^{2} + 8 m = - 3

9 x^{2} + 10 x + 1 = 0

3 + \frac{2 + 7 x}{9} = 9

What are the solutions to the equation -3x^2-4x+4=0 ?
The solutions to the equation -3x^2-4x+4=0 are x=-2,x= 2/3
Find the zeros of -3x^2-4x+4=0
The zeros of -3x^2-4x+4=0 are x=-2,x= 2/3