What are the solutions to the equation (3x+1)^2=0 ?

The solutions to the equation (3x+1)^2=0 are x=-1/3

Find the zeros of (3x+1)^2=0

The zeros of (3x+1)^2=0 are x=-1/3

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(3 x + 1)^{2} = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

(3 x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

2 k^{2} - 3 k - 2

\frac{1}{3} + n = - \frac{1}{2}

4 x - 4 > 3 x + 1

x^{3} - 6 x < x^{2}

2 x^{2} = 4 x + 3

What are the solutions to the equation (3x+1)^2=0 ?
The solutions to the equation (3x+1)^2=0 are x=-1/3
Find the zeros of (3x+1)^2=0
The zeros of (3x+1)^2=0 are x=-1/3