What is factor 2k^2-3k-2 ?

The solution to factor 2k^2-3k-2 is (2k+1)(k-2)

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factor 2k^2-3k-2

factor

2 k^{2} - 3 k - 2

(2 k + 1) (k - 2)

Solution steps

2 k^{2} - 3 k - 2

Break the expression into groups

= (2 k^{2} + k) + (- 4 k - 2)

Factor out

k

from

2 k^{2} + k : k (2 k + 1)

Factor out

- 2

from

- 4 k - 2 : - 2 (2 k + 1)

= k (2 k + 1) - 2 (2 k + 1)

Factor out common term

2 k + 1

= (2 k + 1) (k - 2)

\frac{1}{3} + n = - \frac{1}{2}

4 x - 4 > 3 x + 1

x^{3} - 6 x < x^{2}

2 x^{2} = 4 x + 3

- 2 x^{2} - 8 x - 9 = 0