What are the solutions to the equation -2x^2-8x-9=0 ?

The solutions to the equation -2x^2-8x-9=0 are x=-2-i(sqrt(2))/2 ,x=-2+i(sqrt(2))/2

Find the zeros of -2x^2-8x-9=0

The zeros of -2x^2-8x-9=0 are x=-2-i(sqrt(2))/2 ,x=-2+i(sqrt(2))/2

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- 2 x^{2} - 8 x - 9 = 0

x = - 2 - i \frac{2}{2}, x = - 2 + i \frac{2}{2}

Solution steps

- 2 x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

Simplify

(- 8)^{2} - 4 (- 2) (- 9) : 22 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 2 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 8 ) - 2 2 i}{2 ( - 2 )}

x = \frac{- ( - 8 ) + 2 2 i}{2 ( - 2 )} : - 2 - i \frac{2}{2}

x = \frac{- ( - 8 ) - 2 2 i}{2 ( - 2 )} : - 2 + i \frac{2}{2}

The solutions to the quadratic equation are:

x = - 2 - i \frac{2}{2}, x = - 2 + i \frac{2}{2}

\frac{( x )}{( 2 )} = \frac{( x )}{( 6 )} - \frac{( 1 )}{( 4 )}

3 k^{2} - 18 k - 21 = 0

3 x^{2} - 12 x + 3 = 0

∣ x - 1 ∣ > ∣ 2 x - 1 ∣

x^{2} - x - 72 = 0

What are the solutions to the equation -2x^2-8x-9=0 ?
The solutions to the equation -2x^2-8x-9=0 are x=-2-i(sqrt(2))/2 ,x=-2+i(sqrt(2))/2
Find the zeros of -2x^2-8x-9=0
The zeros of -2x^2-8x-9=0 are x=-2-i(sqrt(2))/2 ,x=-2+i(sqrt(2))/2