What are the solutions to the equation x^2-x-72=0 ?

The solutions to the equation x^2-x-72=0 are x=9,x=-8

Find the zeros of x^2-x-72=0

The zeros of x^2-x-72=0 are x=9,x=-8

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x^{2} - x - 72 = 0

x = 9, x = - 8

Solution steps

x^{2} - x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 72) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

x = \frac{- ( - 1 ) + 17}{2 \cdot 1} : 9

x = \frac{- ( - 1 ) - 17}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 9, x = - 8

x^{2} + 3 x + 8 = 0

(x + 8)^{2} + (x - 6)^{2} = (x + 12)^{2}

(10 \frac{x}{6}) (10 \frac{x}{8}) = 1 0^{10}

0. 4^{2 x + 1} > 0.16

- 4 (r + 2) = 4 (2 - 2 r)

What are the solutions to the equation x^2-x-72=0 ?
The solutions to the equation x^2-x-72=0 are x=9,x=-8
Find the zeros of x^2-x-72=0
The zeros of x^2-x-72=0 are x=9,x=-8