What are the solutions to the equation x^2+3x+8=0 ?

The solutions to the equation x^2+3x+8=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2

Find the zeros of x^2+3x+8=0

The zeros of x^2+3x+8=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2

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x^{2} + 3 x + 8 = 0

x = - \frac{3}{2} + i \frac{23}{2}, x = - \frac{3}{2} - i \frac{23}{2}

Solution steps

x^{2} + 3 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 8 : 23 i

x_{1, 2} = \frac{- 3 \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 23 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 23 i}{2 \cdot 1}

x = \frac{- 3 + 23 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{23}{2}

x = \frac{- 3 - 23 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{23}{2}, x = - \frac{3}{2} - i \frac{23}{2}

(x + 8)^{2} + (x - 6)^{2} = (x + 12)^{2}

(10 \frac{x}{6}) (10 \frac{x}{8}) = 1 0^{10}

0. 4^{2 x + 1} > 0.16

- 4 (r + 2) = 4 (2 - 2 r)

3 x^{2} - 24 x + 36 = 0

What are the solutions to the equation x^2+3x+8=0 ?
The solutions to the equation x^2+3x+8=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2
Find the zeros of x^2+3x+8=0
The zeros of x^2+3x+8=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2