What are the solutions to the equation 3x^2-24x+36=0 ?

The solutions to the equation 3x^2-24x+36=0 are x=6,x=2

Find the zeros of 3x^2-24x+36=0

The zeros of 3x^2-24x+36=0 are x=6,x=2

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3 x^{2} - 24 x + 36 = 0

x = 6, x = 2

Solution steps

3 x^{2} - 24 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 36}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 36 = 12

x_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 3}

x = \frac{- ( - 24 ) + 12}{2 \cdot 3} : 6

x = \frac{- ( - 24 ) - 12}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

x^{2} + 8 x = - 3

\frac{1 - y}{7} + y = \frac{y}{2} + 3

lo g_{8} (\frac{a}{2})

(a + 1) (a + 2) = 0

\frac{1}{2} + \frac{1}{16}

What are the solutions to the equation 3x^2-24x+36=0 ?
The solutions to the equation 3x^2-24x+36=0 are x=6,x=2
Find the zeros of 3x^2-24x+36=0
The zeros of 3x^2-24x+36=0 are x=6,x=2