What are the solutions to the equation x^2+8x=-3 ?

The solutions to the equation x^2+8x=-3 are x=-4+sqrt(13),x=-4-sqrt(13)

Find the zeros of x^2+8x=-3

The zeros of x^2+8x=-3 are x=-4+sqrt(13),x=-4-sqrt(13)

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x^{2} + 8 x = - 3

x = - 4 + 13, x = - 4 - 13

Decimal Notation

x = - 0.39444 \dots, x = - 7.60555 \dots

Solution steps

x^{2} + 8 x = - 3

Move

3

to the left side

x^{2} + 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 3 = 213

x_{1, 2} = \frac{- 8 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 13}{2 \cdot 1}

x = \frac{- 8 + 2 13}{2 \cdot 1} : - 4 + 13

x = \frac{- 8 - 2 13}{2 \cdot 1} : - 4 - 13

The solutions to the quadratic equation are:

x = - 4 + 13, x = - 4 - 13

\frac{1 - y}{7} + y = \frac{y}{2} + 3

lo g_{8} (\frac{a}{2})

(a + 1) (a + 2) = 0

\frac{1}{2} + \frac{1}{16}

∣ 5 x - 2 ∣ + 6 = 6

What are the solutions to the equation x^2+8x=-3 ?
The solutions to the equation x^2+8x=-3 are x=-4+sqrt(13),x=-4-sqrt(13)
Find the zeros of x^2+8x=-3
The zeros of x^2+8x=-3 are x=-4+sqrt(13),x=-4-sqrt(13)