What are the solutions to the equation 3x^2+10x+4=0 ?

The solutions to the equation 3x^2+10x+4=0 are x=(-5+sqrt(13))/3 ,x=-(5+sqrt(13))/3

Find the zeros of 3x^2+10x+4=0

The zeros of 3x^2+10x+4=0 are x=(-5+sqrt(13))/3 ,x=-(5+sqrt(13))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 10 x + 4 = 0

x = \frac{- 5 + 13}{3}, x = - \frac{5 + 13}{3}

Decimal Notation

x = - 0.46481 \dots, x = - 2.86851 \dots

Solution steps

3 x^{2} + 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 4 = 213

x_{1, 2} = \frac{- 10 \pm 2 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 13}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 13}{2 \cdot 3}

x = \frac{- 10 + 2 13}{2 \cdot 3} : \frac{- 5 + 13}{3}

x = \frac{- 10 - 2 13}{2 \cdot 3} : - \frac{5 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{3}, x = - \frac{5 + 13}{3}

6 (a + a + 60) = 324

3 6^{2} + 25 y^{2} = 900

5 x^{2} + 11 x - 12

8 - (\frac{\frac{( 6 - x )}{2}}{3}) = 0

2 x + 11 \geq 17

What are the solutions to the equation 3x^2+10x+4=0 ?
The solutions to the equation 3x^2+10x+4=0 are x=(-5+sqrt(13))/3 ,x=-(5+sqrt(13))/3
Find the zeros of 3x^2+10x+4=0
The zeros of 3x^2+10x+4=0 are x=(-5+sqrt(13))/3 ,x=-(5+sqrt(13))/3