What is factor (a+b)^2-64 ?

The solution to factor (a+b)^2-64 is (a+b+8)(a+b-8)

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factor (a+b)^2-64

factor

(a + b)^{2} - 64

(a + b + 8) (a + b - 8)

Solution steps

(a + b)^{2} - 64

Factor the number:

64 = 8^{2}

= (a + b)^{2} - 8^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a + b)^{2} - 8^{2} = ((a + b) + 8) ((a + b) - 8)

= ((a + b) + 8) ((a + b) - 8)

Apply rule:

(a) = a

(a + b) = a + b

= (a + b + 8) (a + b - 8)

\frac{3}{6}

(x + 10)^{2} + x^{2} = 5 0^{2}

2 (m + 3) - 3 m

\frac{0.45 ( 1 - 0.45 )}{200}

\frac{5 w ^{2} z + 15 w - 140}{w ^{2} + 4 w - 21}