What are the solutions to the equation (x+10)^2+x^2=50^2 ?

The solutions to the equation (x+10)^2+x^2=50^2 are x=30,x=-40

Find the zeros of (x+10)^2+x^2=50^2

The zeros of (x+10)^2+x^2=50^2 are x=30,x=-40

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(x + 10)^{2} + x^{2} = 5 0^{2}

x = 30, x = - 40

Solution steps

(x + 10)^{2} + x^{2} = 5 0^{2}

Expand

(x + 10)^{2} + x^{2} : 2 x^{2} + 20 x + 100

Expand

5 0^{2} : 2500

2 x^{2} + 20 x + 100 = 2500

Move

2500

to the left side

2 x^{2} + 20 x - 2400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 2400 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 2400) = 140

x_{1, 2} = \frac{- 20 \pm 140}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 140}{2 \cdot 2}, x_{2} = \frac{- 20 - 140}{2 \cdot 2}

x = \frac{- 20 + 140}{2 \cdot 2} : 30

x = \frac{- 20 - 140}{2 \cdot 2} : - 40

The solutions to the quadratic equation are:

x = 30, x = - 40

2 (m + 3) - 3 m

\frac{0.45 ( 1 - 0.45 )}{200}

\frac{5 w ^{2} z + 15 w - 140}{w ^{2} + 4 w - 21}

- 4 k^{2} + 2 k + 30

3 x^{4} - 11 x^{2} - 20

What are the solutions to the equation (x+10)^2+x^2=50^2 ?
The solutions to the equation (x+10)^2+x^2=50^2 are x=30,x=-40
Find the zeros of (x+10)^2+x^2=50^2
The zeros of (x+10)^2+x^2=50^2 are x=30,x=-40