What are the solutions to the equation x^2+6x-5=0 ?

The solutions to the equation x^2+6x-5=0 are x=-3+sqrt(14),x=-3-sqrt(14)

Find the zeros of x^2+6x-5=0

The zeros of x^2+6x-5=0 are x=-3+sqrt(14),x=-3-sqrt(14)

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x^{2} + 6 x - 5 = 0

x = - 3 + 14, x = - 3 - 14

Solution steps

x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 5) = 214

x_{1, 2} = \frac{- 6 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 14}{2 \cdot 1}

x = \frac{- 6 + 2 14}{2 \cdot 1} : - 3 + 14

x = \frac{- 6 - 2 14}{2 \cdot 1} : - 3 - 14

The solutions to the quadratic equation are:

x = - 3 + 14, x = - 3 - 14

0 (x) = 7 x^{2} + 4

\frac{x}{6} = 3

325

\frac{5 !}{4 ! ( 5 - 4 ) !}

(4 x + 20) + (5 x + 16) + (x) = 180

What are the solutions to the equation x^2+6x-5=0 ?
The solutions to the equation x^2+6x-5=0 are x=-3+sqrt(14),x=-3-sqrt(14)
Find the zeros of x^2+6x-5=0
The zeros of x^2+6x-5=0 are x=-3+sqrt(14),x=-3-sqrt(14)