What are the solutions to the equation -x^2-7x+10=0 ?

The solutions to the equation -x^2-7x+10=0 are x=-(7+sqrt(89))/2 ,x=(sqrt(89)-7)/2

Find the zeros of -x^2-7x+10=0

The zeros of -x^2-7x+10=0 are x=-(7+sqrt(89))/2 ,x=(sqrt(89)-7)/2

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- x^{2} - 7 x + 10 = 0

x = - \frac{7 + 89}{2}, x = \frac{89 - 7}{2}

Solution steps

- x^{2} - 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

(- 7)^{2} - 4 (- 1) \cdot 10 = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 ( - 1 )}, x_{2} = \frac{- ( - 7 ) - 89}{2 ( - 1 )}

x = \frac{- ( - 7 ) + 89}{2 ( - 1 )} : - \frac{7 + 89}{2}

x = \frac{- ( - 7 ) - 89}{2 ( - 1 )} : \frac{89 - 7}{2}

The solutions to the quadratic equation are:

x = - \frac{7 + 89}{2}, x = \frac{89 - 7}{2}

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What are the solutions to the equation -x^2-7x+10=0 ?
The solutions to the equation -x^2-7x+10=0 are x=-(7+sqrt(89))/2 ,x=(sqrt(89)-7)/2
Find the zeros of -x^2-7x+10=0
The zeros of -x^2-7x+10=0 are x=-(7+sqrt(89))/2 ,x=(sqrt(89)-7)/2