What are the solutions to the equation 8x^2+17x+2=0 ?

The solutions to the equation 8x^2+17x+2=0 are x=-1/8 ,x=-2

Find the zeros of 8x^2+17x+2=0

The zeros of 8x^2+17x+2=0 are x=-1/8 ,x=-2

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8 x^{2} + 17 x + 2 = 0

x = - \frac{1}{8}, x = - 2

Solution steps

8 x^{2} + 17 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

1 7^{2} - 4 \cdot 8 \cdot 2 = 15

x_{1, 2} = \frac{- 17 \pm 15}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 17 + 15}{2 \cdot 8}, x_{2} = \frac{- 17 - 15}{2 \cdot 8}

x = \frac{- 17 + 15}{2 \cdot 8} : - \frac{1}{8}

x = \frac{- 17 - 15}{2 \cdot 8} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{8}, x = - 2

2 x^{2} + 8 x - 18 = 0

\frac{3}{8} p = 9

(x + 2)^{2} = 28

- 5 < x \leq 4

- 12 r + 4 = 100

What are the solutions to the equation 8x^2+17x+2=0 ?
The solutions to the equation 8x^2+17x+2=0 are x=-1/8 ,x=-2
Find the zeros of 8x^2+17x+2=0
The zeros of 8x^2+17x+2=0 are x=-1/8 ,x=-2