What are the solutions to the equation y^2=12y-36 ?

The solutions to the equation y^2=12y-36 are y=6

Find the zeros of y^2=12y-36

The zeros of y^2=12y-36 are y=6

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y^{2} = 12 y - 36

y = 6

Solution steps

y^{2} = 12 y - 36

Move

36

to the left side

y^{2} + 36 = 12 y

Move

12 y

to the left side

y^{2} + 36 - 12 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 12 y + 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 36 = 0

y_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 1}

y = \frac{- ( - 12 )}{2 \cdot 1}

\frac{- ( - 12 )}{2 \cdot 1} = 6

y = 6

The solution to the quadratic equation is:

y = 6

6 x + 3 x - 4 = 14

- 3 (2 x - 4) = 36

x^{2} + x - 20 > 0

5 (x^{2} - 5) + 8 = 8

\frac{3}{4} + \frac{1}{2} + \frac{- 1}{3}

What are the solutions to the equation y^2=12y-36 ?
The solutions to the equation y^2=12y-36 are y=6
Find the zeros of y^2=12y-36
The zeros of y^2=12y-36 are y=6