What are the solutions to the equation 5(x^2-5)+8=8 ?

The solutions to the equation 5(x^2-5)+8=8 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 5(x^2-5)+8=8

The zeros of 5(x^2-5)+8=8 are x=sqrt(5),x=-sqrt(5)

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5 (x^{2} - 5) + 8 = 8

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

5 (x^{2} - 5) + 8 = 8

Move

8

to the right side

5 (x^{2} - 5) = 0

Divide both sides by

5

x^{2} - 5 = 0

Move

5

to the right side

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

\frac{3}{4} + \frac{1}{2} + \frac{- 1}{3}

- x^{2} + x - 2 = 0

4 x^{2} - 19 x - 5 = 0

2 x + 5 < 15

\frac{( 3 x + 2 )}{x - 1} > x

What are the solutions to the equation 5(x^2-5)+8=8 ?
The solutions to the equation 5(x^2-5)+8=8 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 5(x^2-5)+8=8
The zeros of 5(x^2-5)+8=8 are x=sqrt(5),x=-sqrt(5)