What are the solutions to the equation 81x^2+90x+25=0 ?

The solutions to the equation 81x^2+90x+25=0 are x=-5/9

Find the zeros of 81x^2+90x+25=0

The zeros of 81x^2+90x+25=0 are x=-5/9

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81 x^{2} + 90 x + 25 = 0

x = - \frac{5}{9}

Decimal Notation

x = - 0.55555 \dots

Solution steps

81 x^{2} + 90 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 81 \cdot 25}{2 \cdot 81}

9 0^{2} - 4 \cdot 81 \cdot 25 = 0

x_{1, 2} = \frac{- 90 \pm 0}{2 \cdot 81}

x = \frac{- 90}{2 \cdot 81}

\frac{- 90}{2 \cdot 81} = - \frac{5}{9}

x = - \frac{5}{9}

The solution to the quadratic equation is:

x = - \frac{5}{9}

18 x^{2} + 12 x + 2

x + 1 x - 1 \leq 0

x^{2} - \frac{2}{5} x + \frac{1}{25}

(- 512)^{\frac{1}{3}}

\frac{m ^{2} - 6 m + 8}{2 m - 2} \cdot \frac{10}{m - 4}

What are the solutions to the equation 81x^2+90x+25=0 ?
The solutions to the equation 81x^2+90x+25=0 are x=-5/9
Find the zeros of 81x^2+90x+25=0
The zeros of 81x^2+90x+25=0 are x=-5/9