What is the answer to (x+3)/2+(2x-1)/3 =4 ?

The answer to (x+3)/2+(2x-1)/3 =4 is x= 17/7

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(x+3)/2+(2x-1)/3 =4

\frac{x + 3}{2} + \frac{2 x - 1}{3} = 4

x = \frac{17}{7}

Decimal Notation

x = 2.42857 \dots

Solution steps

\frac{x + 3}{2} + \frac{2 x - 1}{3} = 4

Multiply by LCM

3 (x + 3) + 2 (2 x - 1) = 24

Expand

3 (x + 3) + 2 (2 x - 1) : 7 x + 7

7 x + 7 = 24

Move

7

to the right side

7 x = 17

Divide both sides by

7

x = \frac{17}{7}

3 x - x = 2 x

7 - 6 a = 6 - 7 a

x + \frac{3}{4} = 3 + \frac{3}{4}

4 x - 6 = - 8 (6 x - 7) + 42

a, b^{2} = \frac{a}{m} - H

What is the answer to (x+3)/2+(2x-1)/3 =4 ?
The answer to (x+3)/2+(2x-1)/3 =4 is x= 17/7
Solve for x: (x+3)/2+(2x-1)/3 =4
The solution is x= 17/7