What is the answer to solvefor a,b^2= a/m-H ?

The answer to solvefor a,b^2= a/m-H is a=b^2m+Hm;\quad m\ne 0

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solvefor a,b^2= a/m-H

solve for

a, b^{2} = \frac{a}{m} - H

a = b^{2} m + H m; m \neq = 0

Solution steps

b^{2} = \frac{a}{m} - H

Switch sides

\frac{a}{m} - H = b^{2}

Move

H

to the right side

\frac{a}{m} = b^{2} + H

Multiply both sides by

m

a = b^{2} m + H m; m \neq = 0

3 x - 12 = x

2 = 4 m

\frac{1}{3} - 3 = \frac{2}{3} + x

3 x = \frac{6 ( 2 + 3 ^{2} ) - 15}{5}

4 x - 3 + 2 x + 21 = 60

What is the answer to solvefor a,b^2= a/m-H ?
The answer to solvefor a,b^2= a/m-H is a=b^2m+Hm;\quad m\ne 0