What are the solutions to the equation 1/6 x^2-5/6 x+1=0 ?

The solutions to the equation 1/6 x^2-5/6 x+1=0 are x=3,x=2

Find the zeros of 1/6 x^2-5/6 x+1=0

The zeros of 1/6 x^2-5/6 x+1=0 are x=3,x=2

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\frac{1}{6} x^{2} - \frac{5}{6} x + 1 = 0

x = 3, x = 2

Solution steps

\frac{1}{6} x^{2} - \frac{5}{6} x + 1 = 0

Multiply both sides by

6

x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

- x - \frac{4}{5} = x + \frac{1}{2} + \frac{2}{5}

20 (4 a + b)^{2} - 45 (2 a - 3 b)^{2}

\frac{5}{2} (2)^{- 2}

- \frac{4}{10}

4 x^{2} = - 5 x - 3

What are the solutions to the equation 1/6 x^2-5/6 x+1=0 ?
The solutions to the equation 1/6 x^2-5/6 x+1=0 are x=3,x=2
Find the zeros of 1/6 x^2-5/6 x+1=0
The zeros of 1/6 x^2-5/6 x+1=0 are x=3,x=2