What is factor r^2+2rs+s^2-9 ?

The solution to factor r^2+2rs+s^2-9 is (r+s+3)(r+s-3)

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factor r^2+2rs+s^2-9

factor

r^{2} + 2 rs + s^{2} - 9

(r + s + 3) (r + s - 3)

Solution steps

r^{2} + 2 rs + s^{2} - 9

Factor

r^{2} + 2 rs + s^{2} : (r + s)^{2}

= (r + s)^{2} - 9

Factor the number:

9 = 3^{2}

= (r + s)^{2} - 3^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(r + s)^{2} - 3^{2} = ((r + s) + 3) ((r + s) - 3)

= ((r + s) + 3) ((r + s) - 3)

Remove parentheses:

(a) = a

= (r + s + 3) (r + s - 3)

4 x^{2} + 14 x + 21 = 0

(4 x^{5} - 2 x^{3} + 2 x + 3) (4 x^{5} - 2 x^{3} + 2 x + 3)

j^{2} k^{2} + 3 j k^{2}

2 x + 7 - 2 (x - 1) = 3 (x + 3)

\frac{4 ^{2}}{4 ^{- 1}}

What is factor r^2+2rs+s^2-9 ?
The solution to factor r^2+2rs+s^2-9 is (r+s+3)(r+s-3)