What are the solutions to the equation x^2+x-13=0 ?

The solutions to the equation x^2+x-13=0 are x=(-1+sqrt(53))/2 ,x=(-1-sqrt(53))/2

Find the zeros of x^2+x-13=0

The zeros of x^2+x-13=0 are x=(-1+sqrt(53))/2 ,x=(-1-sqrt(53))/2

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x^{2} + x - 13 = 0

x = \frac{- 1 + 53}{2}, x = \frac{- 1 - 53}{2}

Solution steps

x^{2} + x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 13) = 53

x_{1, 2} = \frac{- 1 \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 53}{2 \cdot 1}, x_{2} = \frac{- 1 - 53}{2 \cdot 1}

x = \frac{- 1 + 53}{2 \cdot 1} : \frac{- 1 + 53}{2}

x = \frac{- 1 - 53}{2 \cdot 1} : \frac{- 1 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 53}{2}, x = \frac{- 1 - 53}{2}

12 x^{2} + 29 x + 15

- 5 x \leq 10

x^{3} + x^{2} + x - 3

3 x^{2} + 2 x - 8 = 0

∣ 5 x - 4 ∣ + 4 = 6

What are the solutions to the equation x^2+x-13=0 ?
The solutions to the equation x^2+x-13=0 are x=(-1+sqrt(53))/2 ,x=(-1-sqrt(53))/2
Find the zeros of x^2+x-13=0
The zeros of x^2+x-13=0 are x=(-1+sqrt(53))/2 ,x=(-1-sqrt(53))/2