What are the solutions to the equation 3x^2+2x-8=0 ?

The solutions to the equation 3x^2+2x-8=0 are x= 4/3 ,x=-2

Find the zeros of 3x^2+2x-8=0

The zeros of 3x^2+2x-8=0 are x= 4/3 ,x=-2

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3 x^{2} + 2 x - 8 = 0

x = \frac{4}{3}, x = - 2

Solution steps

3 x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 8) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 3}, x_{2} = \frac{- 2 - 10}{2 \cdot 3}

x = \frac{- 2 + 10}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 2 - 10}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 2

∣ 5 x - 4 ∣ + 4 = 6

6 x - 2 = 4 x + 48

(x - 1) (x + 3) = 12

x^{2} - 4 x + 3

x^{2} - 8 x + 4 > - 3

What are the solutions to the equation 3x^2+2x-8=0 ?
The solutions to the equation 3x^2+2x-8=0 are x= 4/3 ,x=-2
Find the zeros of 3x^2+2x-8=0
The zeros of 3x^2+2x-8=0 are x= 4/3 ,x=-2