What is factor j^2-5j-14 ?

The solution to factor j^2-5j-14 is (j+2)(j-7)

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factor j^2-5j-14

factor

j^{2} - 5 j - 14

(j + 2) (j - 7)

Solution steps

j^{2} - 5 j - 14

Break the expression into groups

= (j^{2} + 2 j) + (- 7 j - 14)

Factor out

j

from

j^{2} + 2 j : j (j + 2)

Factor out

- 7

from

- 7 j - 14 : - 7 (j + 2)

= j (j + 2) - 7 (j + 2)

Factor out common term

j + 2

= (j + 2) (j - 7)

3 x + 5 = 2

\frac{- 7}{- 2}

2 (8 x - 4) - 2 x \leq 14 x + 12

- \frac{2}{3} a + \frac{5}{6} a - \frac{1}{6}

\frac{( - 35 x y ) ^{4}}{( 14 x yz ) ^{4}}