What are the solutions to the equation (x-2)^2=-3 ?

The solutions to the equation (x-2)^2=-3 are x=sqrt(3)i+2,x=-sqrt(3)i+2

Find the zeros of (x-2)^2=-3

The zeros of (x-2)^2=-3 are x=sqrt(3)i+2,x=-sqrt(3)i+2

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(x - 2)^{2} = - 3

x = 3 i + 2, x = - 3 i + 2

Solution steps

(x - 2)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 3 : x = 3 i + 2

Solve

x - 2 = - - 3 : x = - 3 i + 2

The solutions to the quadratic equation are:

x = 3 i + 2, x = - 3 i + 2

v^{2} + 4 v - 21

2 x^{2} - x = 6

4 x^{2} + 9 = 0

x^{3} > x^{2}

\frac{1}{4} (m + 8) > \frac{1}{2}

What are the solutions to the equation (x-2)^2=-3 ?
The solutions to the equation (x-2)^2=-3 are x=sqrt(3)i+2,x=-sqrt(3)i+2
Find the zeros of (x-2)^2=-3
The zeros of (x-2)^2=-3 are x=sqrt(3)i+2,x=-sqrt(3)i+2