en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^4+2x^3-4x^2-8x>= 0

Solution

x^{4} + 2 x^{3} - 4 x^{2} - 8 x \geq 0

Solution

x \leq 0 or x \geq 2

+1

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

x^{4} + 2 x^{3} - 4 x^{2} - 8 x \geq 0

Factor

x^{4} + 2 x^{3} - 4 x^{2} - 8 x : x (x + 2)^{2} (x - 2)

x (x + 2)^{2} (x - 2) \geq 0

Identify the intervals

x \leq 0 or x \geq 2

Popular Examples

∣ - x + 2 ∣ - 13 > 17

simplify (1-a)/(a^2-a+1)+(a^2)/(a^3+1)simplify

\frac{1 - a}{a ^{2} - a + 1} + \frac{a ^{2}}{a ^{3} + 1}

simplify (31)/(\frac{25){12/25}}simplify

\frac{31}{\frac{25}{\frac{12}{25}}}

w+w+(2w-2)+(2w-2)=11

w + w + (2 w - 2) + (2 w - 2) = 11

simplify 3^8 simplify

3^{8}

Frequently Asked Questions (FAQ)

What is x^4+2x^3-4x^2-8x>= 0 ?
The solution to x^4+2x^3-4x^2-8x>= 0 is x<= 0\lor x>= 2