What are the solutions to the equation 3x(x+2)=5 ?

The solutions to the equation 3x(x+2)=5 are x=(-3+2sqrt(6))/3 ,x=-(3+2sqrt(6))/3

Find the zeros of 3x(x+2)=5

The zeros of 3x(x+2)=5 are x=(-3+2sqrt(6))/3 ,x=-(3+2sqrt(6))/3

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3 x (x + 2) = 5

x = \frac{- 3 + 2 6}{3}, x = - \frac{3 + 2 6}{3}

Solution steps

3 x (x + 2) = 5

Expand

3 x (x + 2) : 3 x^{2} + 6 x

3 x^{2} + 6 x = 5

Move

5

to the left side

3 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 5) = 46

x_{1, 2} = \frac{- 6 \pm 4 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 4 6}{2 \cdot 3}, x_{2} = \frac{- 6 - 4 6}{2 \cdot 3}

x = \frac{- 6 + 4 6}{2 \cdot 3} : \frac{- 3 + 2 6}{3}

x = \frac{- 6 - 4 6}{2 \cdot 3} : - \frac{3 + 2 6}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 6}{3}, x = - \frac{3 + 2 6}{3}

3 x^{2} - 16 x - 4 = 0

12 x^{2} - 60 x + 44

3 x + 5 = 3 (x + 5)

2 (- n - 3) - 7 (5 + 2 n)

s^{4} + s^{3} - s^{2} - s

What are the solutions to the equation 3x(x+2)=5 ?
The solutions to the equation 3x(x+2)=5 are x=(-3+2sqrt(6))/3 ,x=-(3+2sqrt(6))/3
Find the zeros of 3x(x+2)=5
The zeros of 3x(x+2)=5 are x=(-3+2sqrt(6))/3 ,x=-(3+2sqrt(6))/3