What are the solutions to the equation x^2-41x+420=0 ?

The solutions to the equation x^2-41x+420=0 are x=21,x=20

Find the zeros of x^2-41x+420=0

The zeros of x^2-41x+420=0 are x=21,x=20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 41 x + 420 = 0

x = 21, x = 20

Solution steps

x^{2} - 41 x + 420 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 1 \cdot 420}{2 \cdot 1}

(- 41)^{2} - 4 \cdot 1 \cdot 420 = 1

x_{1, 2} = \frac{- ( - 41 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 41 ) - 1}{2 \cdot 1}

x = \frac{- ( - 41 ) + 1}{2 \cdot 1} : 21

x = \frac{- ( - 41 ) - 1}{2 \cdot 1} : 20

The solutions to the quadratic equation are:

x = 21, x = 20

x^{4} - 25 x^{2} + 4 x^{3} - 100 x + 3 x^{2} - 75

(3 x - 5)^{2} = 21

\frac{2 x - 1}{3} - \frac{5 x - 6}{6} = - 2

\frac{∣ x - 1 ∣}{∣ x + 1 ∣} < 1

14 x^{2} + 13 x - 12

What are the solutions to the equation x^2-41x+420=0 ?
The solutions to the equation x^2-41x+420=0 are x=21,x=20
Find the zeros of x^2-41x+420=0
The zeros of x^2-41x+420=0 are x=21,x=20