What is (|x-1|)/(|x+1|)<1 ?

The solution to (|x-1|)/(|x+1|) 0

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(|x-1|)/(|x+1|)<1

\frac{∣ x - 1 ∣}{∣ x + 1 ∣} < 1

x > 0

Interval Notation

(0, \infty)

Solution steps

\frac{∣ x - 1 ∣}{∣ x + 1 ∣} < 1

Find positive and negative intervals

x < - 1, - 1 \leq x < 1, x \geq 1

Solve the inequality for each interval

No Solution or 0 < x < 1 or x \geq 1

Merge Overlapping Intervals

x > 0

14 x^{2} + 13 x - 12

\frac{5 x ^{4} y ^{2}}{25 x ^{3} y ^{5}}

- 7 < x < 5

x^{2} - 2 x - 1 = 4

x^{2} - 7 + 12 = 0