What are the solutions to the equation x^2-7+12=0 ?

The solutions to the equation x^2-7+12=0 are x=sqrt(5)i,x=-sqrt(5)i

Find the zeros of x^2-7+12=0

The zeros of x^2-7+12=0 are x=sqrt(5)i,x=-sqrt(5)i

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x^{2} - 7 + 12 = 0

x = 5 i, x = - 5 i

Solution steps

x^{2} - 7 + 12 = 0

Move

7

to the right side

x^{2} + 12 = 7

Move

12

to the right side

x^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 5, x = - - 5

- 5 = 5 i

- - 5 = - 5 i

x = 5 i, x = - 5 i

1 + 8 t^{3}

(x^{\frac{5}{6}}) (x^{\frac{1}{3}})

2 (- 1) + 1

(\frac{1}{x ^{2} - 4 x - 5})^{\frac{1}{2}}

4 x^{2} + x - 18 = 0

What are the solutions to the equation x^2-7+12=0 ?
The solutions to the equation x^2-7+12=0 are x=sqrt(5)i,x=-sqrt(5)i
Find the zeros of x^2-7+12=0
The zeros of x^2-7+12=0 are x=sqrt(5)i,x=-sqrt(5)i