What is (1/(x^2-4x-5))^{1/2} ?

The solution to (1/(x^2-4x-5))^{1/2} is 1/((x^2-4x-5)^{1/2)}

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simplify (1/(x^2-4x-5))^{1/2}

simplify

(\frac{1}{x ^{2} - 4 x - 5})^{\frac{1}{2}}

\frac{1}{( x ^{2} - 4 x - 5 ) ^{\frac{1}{2}}}

Solution steps

(\frac{1}{x ^{2} - 4 x - 5})^{\frac{1}{2}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{\frac{1}{2}}}{( x ^{2} - 4 x - 5 ) ^{\frac{1}{2}}}

Apply rule

1^{a} = 1

1^{\frac{1}{2}} = 1

= \frac{1}{( x ^{2} - 4 x - 5 ) ^{\frac{1}{2}}}

4 x^{2} + x - 18 = 0

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\frac{4}{3} \cdot π \cdot 3^{3}

\frac{3}{a} + \frac{7}{b}

What is (1/(x^2-4x-5))^{1/2} ?
The solution to (1/(x^2-4x-5))^{1/2} is 1/((x^2-4x-5)^{1/2)}