What is the answer to 5(a+3)+4a-5=-(2a-4) ?

The answer to 5(a+3)+4a-5=-(2a-4) is a=-6/11

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5(a+3)+4a-5=-(2a-4)

5 (a + 3) + 4 a - 5 = - (2 a - 4)

a = - \frac{6}{11}

Solution steps

5 (a + 3) + 4 a - 5 = - (2 a - 4)

Expand

5 (a + 3) + 4 a - 5 : 9 a + 10

Expand

- (2 a - 4) : - 2 a + 4

9 a + 10 = - 2 a + 4

Move

10

to the right side

9 a = - 2 a - 6

Move

2 a

to the left side

11 a = - 6

Divide both sides by

11

a = - \frac{6}{11}

3 x - \frac{1}{2} = \frac{x}{2} + 2 x

3 (2 - x) + 4 x = 6 - [3 - (2 - 2 x)]

M = \frac{( 1 + i ) ^{1} 1}{( 32 ( 1 - i ) )}

c, 3 c + 4 d = 5

a^{2} x + (a - 5) = (a + 5) x

What is the answer to 5(a+3)+4a-5=-(2a-4) ?
The answer to 5(a+3)+4a-5=-(2a-4) is a=-6/11
Solve for a: 5(a+3)+4a-5=-(2a-4)
The solution is a=-6/11