What are the solutions to the equation 0=x^2+2(0.7)x-0.4125 ?

The solutions to the equation 0=x^2+2(0.7)x-0.4125 are x=(-1.4+sqrt(3.61))/2 ,x=(-1.4-sqrt(3.61))/2

Find the zeros of 0=x^2+2(0.7)x-0.4125

The zeros of 0=x^2+2(0.7)x-0.4125 are x=(-1.4+sqrt(3.61))/2 ,x=(-1.4-sqrt(3.61))/2

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0 = x^{2} + 2 (0.7) x - 0.4125

x = \frac{- 1.4 + 3.61}{2}, x = \frac{- 1.4 - 3.61}{2}

Solution steps

0 = x^{2} + 2 (0.7) x - 0.4125

Expand

x^{2} + 2 (0.7) x - 0.4125 : x^{2} + 1.4 x - 0.4125

0 = x^{2} + 1.4 x - 0.4125

Switch sides

x^{2} + 1.4 x - 0.4125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1.4 \pm 1. 4 ^{2} - 4 \cdot 1 \cdot ( - 0.4125 )}{2 \cdot 1}

1. 4^{2} - 4 \cdot 1 \cdot (- 0.4125) = 3.61

x_{1, 2} = \frac{- 1.4 \pm 3.61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1.4 + 3.61}{2 \cdot 1}, x_{2} = \frac{- 1.4 - 3.61}{2 \cdot 1}

x = \frac{- 1.4 + 3.61}{2 \cdot 1} : \frac{- 1.4 + 3.61}{2}

x = \frac{- 1.4 - 3.61}{2 \cdot 1} : \frac{- 1.4 - 3.61}{2}

The solutions to the quadratic equation are:

x = \frac{- 1.4 + 3.61}{2}, x = \frac{- 1.4 - 3.61}{2}

10 x^{2} + 33 x - 7

\frac{( 3 ab c ) ^{3}}{( 2 a ^{- 1} b ^{- 2} c ) ^{2}}

3 w^{2} - 21 w = 0

x^{2} - 29 x + 198

171

What are the solutions to the equation 0=x^2+2(0.7)x-0.4125 ?
The solutions to the equation 0=x^2+2(0.7)x-0.4125 are x=(-1.4+sqrt(3.61))/2 ,x=(-1.4-sqrt(3.61))/2
Find the zeros of 0=x^2+2(0.7)x-0.4125
The zeros of 0=x^2+2(0.7)x-0.4125 are x=(-1.4+sqrt(3.61))/2 ,x=(-1.4-sqrt(3.61))/2