What is the answer to (6x^2-12)/(3x-4)=2x ?

The answer to (6x^2-12)/(3x-4)=2x is x= 3/2

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(6x^2-12)/(3x-4)=2x

\frac{6 x ^{2} - 12}{3 x - 4} = 2 x

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

\frac{6 x ^{2} - 12}{3 x - 4} = 2 x

Multiply both sides by

3 x - 4

6 x^{2} - 12 = 2 x (3 x - 4)

Expand

2 x (3 x - 4) : 6 x^{2} - 8 x

6 x^{2} - 12 = 6 x^{2} - 8 x

Move

12

to the right side

6 x^{2} = 6 x^{2} - 8 x + 12

Subtract

6 x^{2} - 8 x

from both sides

6 x^{2} - (6 x^{2} - 8 x) = 6 x^{2} - 8 x + 12 - (6 x^{2} - 8 x)

Simplify

8 x = 12

Divide both sides by

8

x = \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = \frac{4}{3}

Combine undefined points with solutions:

x = \frac{3}{2}

(3 x - 1)^{- 1} = 2 x^{- 1}

2 + \frac{2}{x} = 3

\frac{6}{x + 6} = \frac{5}{x + 5}

\frac{6}{b - 1} = \frac{9}{7}

10 - \frac{13}{x} = 4 + \frac{5}{x}

What is the answer to (6x^2-12)/(3x-4)=2x ?
The answer to (6x^2-12)/(3x-4)=2x is x= 3/2
Solve for x: (6x^2-12)/(3x-4)=2x
The solution is x= 3/2